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(F)=-4F^2+2F-5
We move all terms to the left:
(F)-(-4F^2+2F-5)=0
We get rid of parentheses
4F^2-2F+F+5=0
We add all the numbers together, and all the variables
4F^2-1F+5=0
a = 4; b = -1; c = +5;
Δ = b2-4ac
Δ = -12-4·4·5
Δ = -79
Delta is less than zero, so there is no solution for the equation
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